Turnuvalar / Challenger

ATP Singles: Augsburg challenger

Challenger 110 maç · 17 Ağustos 2025 - 23 Ağustos 2025

Kuradaki en yüksek puanlı oyuncular

Nicod J.Puan1663 Luka MikrutPuan1637 Paroulek T.Puan1619 Vives Marcos P.Puan1610 Torres J.Puan1604 Maks KasnikowskiPuan1603 Cacao T.Puan1603 Lopez Morillo I.Puan1601 Strombachs R.Puan1601 Sheyngezikht L.Puan1594

Sonuçlar

23 Ağustos 2025 1 maç

Stebe C.1–2Ritschard A.H2H ›

22 Ağustos 2025 2 maç

Kolar Z.2–1Stebe C.H2H ›
Ritschard A.2–1Negritu C.H2H ›

21 Ağustos 2025 4 maç

Sanchez Izquierdo N.1–2Squire H.H2H ›
Stebe C.2–0Cerny M.H2H ›
Sanchez Martinez B.0–2Kolar Z.H2H ›
Ritschard A.2–0Schoenhaus M.H2H ›

20 Ağustos 2025 8 maç

Ritschard A.2–0Schoenhaus M.H2H ›
Kolar Z.1–2Barton H.H2H ›
Squire H.2–1Montes-De La Torre I.H2H ›
Stebe C.2–0Gadamauri B.H2H ›
Popovic S.0–2Negritu C.H2H ›
Sanchez Izquierdo N.1–2Dedura-Palomero D.H2H ›
Bailly G.2–0Sanchez Martinez B.H2H ›
Cerny M.0–2Paroulek T.H2H ›

19 Ağustos 2025 10 maç

Marterer M.2–1Negritu C.H2H ›
Berrettini J.2–1Gadamauri B.H2H ›
Strombachs R.0–2Cerny M.H2H ›
Ehrenschneider N.2–1Popovic S.H2H ›
Kolar Z.1–2Mikrut L.H2H ›
Poljicak M.2–1Stebe C.H2H ›
Paroulek T.2–0Denolly C.H2H ›
Prado Angelo J.2–1Bailly G.H2H ›
Torres J.1–2Squire H.H2H ›
Masur D.0–2Sanchez Martinez B.H2H ›

18 Ağustos 2025 54 maç

Martin A.1–2Dedura-Palomero D.H2H ›
Petkovic M.0–2Barton H.H2H ›
Sanchez Izquierdo N.2–1Brancaccio R.H2H ›
Bol J.2–1Cado Z.H2H ›
Tailleu P.2–1Hell J.H2H ›
Piening C.2–1Van Zijl T.H2H ›
Montes-De La Torre I.2–0Zahraj P.H2H ›
Ritschard A.1–2Molleker R.H2H ›
Schoenhaus M.0–2Nicod J.H2H ›
Langenaken L.2–1Tixhon D.H2H ›
Bredschneijder O.2–1Kayombo G.H2H ›
Bouwman B.2–1Le Meur R.H2H ›
Walch A.2–1Galliano L.H2H ›
Tanner G.2–1Ros Mesas M.H2H ›
Lopez Escribano A.0–2Cacao T.H2H ›
Maia H.2–0Hou Y.H2H ›
Paroulek T.2–0Steiner M.H2H ›
Popovic S.2–0Covato M.H2H ›
Lopez Morillo I.2–0Ehrenschneider N.H2H ›
Burdet A.2–1Vitter B.H2H ›
Venger R.2–1Wieland L.H2H ›
Hartenstein J.2–1Poels M.H2H ›
Verwerft L.2–1Vermeer W.H2H ›
Van Donselaar F.2–1Van Nunen M.H2H ›
Tremblay D.2–1Jux M.H2H ›
Valdoleiros G.2–0Freitas J.H2H ›
Robert N.2–0Coelho D.H2H ›
Molokova Ferreira D.1–2Rodeia A.H2H ›
Kasnikowski M.2–0Gadamauri B.H2H ›
Barsukov N.0–2Sanchez Martinez B.H2H ›
Arias B.0–2Cerny M.H2H ›
Van Leeuwen P.2–1Schroeter M.H2H ›
Verbeek D.2–1Megrabian A.H2H ›
Miller D.2–1Visser M.H2H ›
Lazaro Juncadella M.2–1Goldberg Alviani N.H2H ›
Sheyngezikht L.2–1Garcia Mestre J.H2H ›
Cordoba C.2–1Regas Luis N.H2H ›
Pop D.2–1Peiro Serrano A.H2H ›
Bianchi J.2–0Molenkamp M.H2H ›
Sychev P.2–1Mendes J.H2H ›
Hansson J.0–2Fradkin J.H2H ›
Bessonov D.0–2Kim D.H2H ›
Takahata R.2–0Mehrotra A.H2H ›
Sukkho P.0–2Minakata R.H2H ›
Koaykul K.2–0Khantiweerawat T.H2H ›
Chung Y.2–1Zhou X.H2H ›
Nakamura R.2–0Hung K.H2H ›
Tomida Y.2–0Sharma A.H2H ›
Aggarwal P.0–2Navasirisomboon J.H2H ›
Lee J.2–0Ganta S.H2H ›
Park Y.2–0Lin Y.H2H ›
Yin B.2–1Mercier T.H2H ›
Fu H.2–0Lu C.H2H ›
Wang Y.0–2Pawar S.H2H ›

17 Ağustos 2025 31 maç

Uzhylovsky V.2–1Covato M.H2H ›
Held J.0–2Ehrenschneider N.H2H ›
Hartig R.2–1Poels M.H2H ›
Martens N.2–1Hell J.H2H ›
Jakupi J.2–1Kypriotis E.H2H ›
Duda F.2–1Steiner M.H2H ›
Ymer M.2–0Hellum Lilleengen L.H2H ›
Schifris J.0–2Cerny M.H2H ›
Van Nunen M.2–1Luttig J.H2H ›
Miller D.2–1Vanderstappen Z.H2H ›
Vermeer W.2–1Martinez Mora Esdras W.H2H ›
Bellifemine A.2–1Gadamauri B.H2H ›
Guerrieri A.2–1Barsukov N.H2H ›
Sanchez Martinez B.2–1Donald M.H2H ›
Megrabian A.2–1Miller A.H2H ›
Jux M.2–1Gomez Osorio A.H2H ›
Lofink M.2–1Cado Z.H2H ›
Hediger I.2–1Senn N.H2H ›
Bessonov D.2–0Ingale P.H2H ›
Nithithananont N.0–2Kim D.H2H ›
Takahata R.2–0Thadpong K.H2H ›
Congcar C.2–1Mehrotra A.H2H ›
Kodancha Srinivasan D.2–0Sukkho P.H2H ›
Minakata R.0–2Van Herzeele J.H2H ›
Beckles D.2–1Koaykul K.H2H ›
Van Aken N.2–1Ganta S.H2H ›
Srirat T.0–2Navasirisomboon J.H2H ›
Khantiweerawat T.0–2Karra T.H2H ›
Bangargi A.0–2Sharma A.H2H ›
Lee J.2–0Duddupudi A.H2H ›
Aggarwal P.2–0Sriwong P.H2H ›
Bu tahminler nasıl yapılıyor
Gelecek maçlarda sitenin geri kalanıyla aynı modelden gelen tahmin var. Biten maçlarda yalnızca sonuç gösterilir: bu sonucu zaten içeren puanlarla sonradan hesaplanan bir tahmin modeli olduğundan iyi gösterirdi.